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AEE Certified Energy Manager (CEM) Sample Questions (Q79-Q84):
NEW QUESTION # 79
Thermal scans of electrical equipment are useful for:
Answer: A
Explanation:
Step 1: Purpose of Thermal Scans
Thermal scans (infrared thermography) detecttemperature variationsin electrical components.
* Loose connectionsincrease resistance # causeoverheating, which isvisible in thermal scans.
Step 2: Analysis of Each Option
* A. Locating areas of high power factor#Incorrect#Power factor is measured with power meters.
* B. Reading current-carrying capacity of conductors#Incorrect#Measured using ammeters and engineering data.
* C. Locating a loose electrical connection#Correct#Loose connections causeheat buildup, easily detected with thermal scans.
* D. Measuring the load on a refrigerant system#Incorrect#Refrigerant loads are measured using pressure sensors and flow meters.
Thus, the correct answer isC. Locating a loose electrical connection.
NEW QUESTION # 80
An air conditioning unit cools make-up air from 25°C (dry bulb temperature) and 50% relative humidity down to 13°C. What type of heat has been removed from the air?
Answer: C
NEW QUESTION # 81
Using the lumen method, calculate the number of luminaires (fixtures) required to light a room to 200 lux.
Each luminaire has 2 fluorescent lamps, 3,000 lumens per lamp. The room is 20 meters by 30 meters. The total light loss factor (LLF) is 0.70 and the luminaire coefficient of utilization (CU) is 0.80.
Answer: C
NEW QUESTION # 82
Natural gas costs $4.80/GJ. How much does it cost to heat 500 liters of water from 18°C to 50°C using a natural gas water heater with an efficiency of 85%? [The efficiency and fuel price are both based on HHV.
The specific heat of water (C) is 4.2 kJ/kg-°C.]
Answer: C
Explanation:
To calculate the cost of heating water using natural gas:
Step 1: Compute Energy Required to Heat the Water
Given:
* Mass of water= 500 L = 500 kg
* Temperature rise (#T)= 50°C - 18°C = 32°C
* Specific heat of water (Cp)= 4.2 kJ/kg-°C
Energy Required (Q)=m×Cp×#T
=500×4.2×32
=67,200 kJ=67.2 MJ
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NEW QUESTION # 83
According to the institute of Electrical and Electronic Engineers (IEEE) standard 519. "Recommended Practices and Requirements for Harmonic Control in Electrical Power Systems." the maximum total harmonic distortion (THD) for general low voltage systems less than 600 votts) should be:
SELECT THE CORRECT ANSWER
Answer: D
Explanation:
The Institute of Electrical and Electronics Engineers (IEEE) Standard 519, titled "Recommended Practices and Requirements for Harmonic Control in Electrical Power Systems," sets forth guidelines to maintain the quality of electrical power by limiting harmonic distortions. According to IEEE 519, for general low-voltage systems (defined as systems with a voltage less than 600 volts), the Total Harmonic Distortion (THD) of the voltage waveform should not exceed 5%. This threshold ensures the reliable operation of electrical equipment and minimizes potential issues such as overheating or malfunctioning caused by excessive harmonics.
Therefore, the correct answer is C. Less than 5%.
NEW QUESTION # 84
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